If $l\left( x \right)$ is the least integer not less than $x$ and $g\left( x \right)$ is the greatest integer not greater than $x$, then $\mathop {\lim }\limits_{x \to e + \pi } \left\{ {l\left( x \right) + g\left( x \right)} \right\}$ is equal to

JEE MATHEMATICS MCQ: LIMITS

1 Easy

1 of 1

Application +4 | -1

l\left( x \right)

is the least integer not less than

x

and

g\left( x \right)

is the greatest integer not greater than

x

, then

\lim\limits_{x \to e + \pi } \left\{ {l\left( x \right) + g\left( x \right)} \right\}

is equal to

View answer and explanation

Correct option: D

None of these

Option D (None of these) is correct because the limit evaluates to 11, which is not among the provided options.