A progressive wave ${\rm{y = a}}\,{\rm{sin}}\left[ {\left( {{\rm{kx}} - {\rm{\omega t}}} \right)} \right]$ is reflected by a rigid wall at ${\rm{x}} = 0$. Then the reflected wave can be represented by

$\begin{array}{*{20}{l}} {{\rm{y = }} - {\rm{asin}}\left( {{\rm{kx + \omega t}}} \right)} \end{array}$

${\rm{y = a}}\,{\rm{sin}}\left( {{\rm{kx + \omega t}}} \right)$

$\begin{array}{*{20}{l}} {{\rm{y = a}}\,{\rm{cos}}\left( {{\rm{kx + \omega t}}} \right)} \end{array}$

$\begin{array}{*{20}{l}} {{\rm{y}} = - {\rm{asin}}\left( {{\rm{kx}} - {\rm{\omega t}}} \right)} \end{array}$

JEE PHYSICS MCQ: WAVES

1 Medium

1 of 1

Understanding +4 | -1

A progressive wave 

\mathrm{y = a}\,\mathrm{sin}\left[ {\left( {\mathrm{kx} - \mathrm{\omega t}} \right)} \right]

is reflected by a rigid wall at

\mathrm{x} = 0

. Then the reflected wave can be represented by

View answer and explanation

Correct option: D

\begin{array}{llllllllllllllllllll} {\mathrm{y = } - \mathrm{asin}\left( {\mathrm{kx + \omega t}} \right)} \end{array}

Option D is correct because reflection from a rigid wall introduces a phase change of π, resulting in a negative sign and a change in direction.

Practice All Chapter MCQs →

3\,\,kHz

0.5

f\mathrm{ }Hz

V\mathrm{ }m/sec

0.2\,\,V

y = \frac{3}{{{{\left( {2x + 3t} \right)}^2} + 4}},

(– \mathrm{ve}) \,x

y = f(kx +\omega t),

X

0.01\,\,s

5 \mathrm{~m}

245 \mathrm{~g}

1 \mathrm{~kg}

g=980 \mathrm{~cm} \mathrm{~s}^{-2}

T

V