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JEE MATHEMATICS MCQ: INVERSE TRIGONOMETRY

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Application +4 | -1
If tan⁡−1x−tan⁡−1y=tan⁡−1A\tan ^{-1} x-\tan ^{-1} y=\tan ^{-1} A, and xy>−1x y>-1, then AA is
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Correct option: C
x−y1+xy\frac{x-y}{1+x y}
Option C (x−y1+xy\frac{x-y}{1+xy}) is correct because using the tangent subtraction formula, tan⁡−1x−tan⁡−1y=tan⁡−1x−y1+xy\tan^{-1} x - \tan^{-1} y = \tan^{-1} \frac{x-y}{1+xy}, which directly gives the value of A.

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