Calculate the root mean square speed of $\mathrm{H}_2$ molecules under following condition. (a) 2 mole of $\mathrm{H}_2$ at $27^{\circ} \mathrm{C}$. (b) 3 mole of $\mathrm{H}_2$ in a 5 lit container at $10^5 \mathrm{~Pa}$.

(a) $1934.24 \mathrm{~m} / \mathrm{sec};$ (b) $250 \mathrm{~m} / \mathrm{sec}$

(a) $1349.44 \mathrm{~m} / \mathrm{sec};$ (b) $500 \mathrm{~m} / \mathrm{sec}$

(a) $1446.19 \mathrm{~m} / \mathrm{sec};$ (b) $390 \mathrm{~m} / \mathrm{sec}$

JEE CHEMISTRY MCQ: STATES OF MATTER

1 Hard

1 of 1

Application +4 | -1

Calculate the root mean square speed of

\mathrm{H}_2

molecules under following condition.
(a) 2 mole of

\mathrm{H}_2

27^{\circ} \mathrm{C}

.
(b) 3 mole of

\mathrm{H}_2

in a 5 lit container at

10^5 \mathrm{~Pa}

View answer and explanation

Correct option: A

(a)

1934.24 \mathrm{~m} / \mathrm{sec};

(b)

500 \mathrm{~m} / \mathrm{sec}

Option A ((a)

1934.24 \mathrm{~m} / \mathrm{sec};

(b)

500 \mathrm{~m} / \mathrm{sec}

) is correct because it correctly calculates the root mean square speed using the given conditions.

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30 \mathrm{~mL}