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JEE PHYSICS MCQ: WAVE OPTICS

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The time period of rotation of the sun is 25 days and its radius is 7×108  m7 \times {10^8}\;m. The Doppler shift for the light of wavelength 6000A∘6000\mathop \mathrm{A}\limits^ \circ emitted from the surface of the sun will be
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Correct option: A
0.04A∘0.04\mathop \mathrm{A}\limits^ \circ
Option A (0.04A∘0.04\mathop \mathrm{A}\limits^ \circ) is correct because it is calculated using the Doppler shift formula and the sun's rotational velocity.

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