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NEET UG PHYSICS MCQ: UNITS & MEASUREMENTS

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Application +4 | -1
The dimensional formula of coefficient of permittivity for free space (ε0)\left( {{\varepsilon _0}} \right) in the equation F=14πε0q1q2r2,F = \frac{1}{{4\mathrm{\pi }{\varepsilon _0}}}\frac{{{q_1}{q_2}}}{{{r^2}}}, where symbols have their usual meanings, is
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Correct option: B
[M−1L−3T4A2]\left[ {{\mathrm{M}^{ - 1}}{\mathrm{L}^{ - 3}}{\mathrm{T}^4}{\mathrm{A}^2}} \right]
Option B ([M−1L−3T4A2][{\mathrm{M}^{ - 1}}{\mathrm{L}^{ - 3}}{\mathrm{T}^4}{\mathrm{A}^2}]) is correct because it correctly derives the dimensional formula of permittivity using Coulomb's law.

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