NEET UG CHEMISTRY MCQ: THERMODYNAMICS

1 Medium

1 of 1

Analyzing +4 | -1

Statement-I : At equilibrium

\Delta {G^0}

always zero.
Statement-II : At STP active masses of 11.2 L of

{O_2}\left( g \right)

and 5.6 L of

{N_2}\left( g \right)

are equal.

View answer and explanation

Correct option: D

Statement I is wrong, Statement II is correct

Statement I is wrong because

\Delta G^0

is zero at equilibrium only under standard conditions. Statement II is correct because active mass is proportional to moles, and the number of moles are equal for 11.2 L of O2 and 5.6 L of N2 at STP.

More Questions from THERMODYNAMICS

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The internal energy of one mole of a gas is: An ideal gas is allowed to expand both reversibly and irreversibly in an isolated system. If

{T_i}

is the initial temperature and

{T_f}

is the final temperature, which of the following statements is correct? For which of the process, ∆S is negative? The work done by a weightless piston in causing an expansion ∆V (at constant temperature), when the opposing pressure, P is variable, is given by: Assertion :- At constant pressure of the change

\mathrm{H}_2 \mathrm{O}(\mathrm{s}) \rightarrow \mathrm{H}_2 \mathrm{O}(\mathrm{g})

work done is negative.

Reason :- During phase transition work done is always negative. For the reaction,

\mathrm{X}_2 \mathrm{O_4(l}) \longrightarrow 2 \mathrm{XO}_2(\mathrm{g}), \Delta U=2.1 \mathrm{~kcal}, \Delta S=20 \mathrm{~cal} \mathrm{~K}^{-1}

300 \mathrm{~K}

. Hence,

\Delta G