When ${\rm{HCHO}}$ is treated with ${{\rm{C}}_6}{{\rm{H}}_5}{\rm{CHO}}$ in presence of NaOH, the products are:

${\rm{HCOONa }}\;{\rm{and}}\;{{\rm{C}}_6}{{\rm{H}}_5}{\rm{C}}{{\rm{H}}_2}{\rm{OH}}$

${\rm{C}}{{\rm{H}}_3}{\rm{OH}}\;and{\rm{ }}HCOONa$

${{\rm{C}}_6}{{\rm{H}}_5}{\rm{C}}{{\rm{H}}_2}{\rm{OH }}\;{\rm{and}}\;{{\rm{C}}_6}{{\rm{H}}_5}{\rm{COONa}}$

${\rm{C}}{{\rm{H}}_3}{\rm{OH }}\;{\rm{and}}\;{{\rm{C}}_6}{{\rm{H}}_5}{\rm{COONa}}$

JEE CHEMISTRY MCQ: ALDEHYDES & KETONES & CARBOXYLIC ACIDS

1 Medium

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Application +4 | -1

When

\mathrm{HCHO}

is treated with

{\mathrm{C}_6}{\mathrm{H}_5}\mathrm{CHO}

in presence of NaOH, the products are:

View answer and explanation

Correct option: D

\mathrm{HCOONa }\;\mathrm{and}\;{\mathrm{C}_6}{\mathrm{H}_5}\mathrm{C}{\mathrm{H}_2}\mathrm{OH}

Option D (

\mathrm{HCOONa }\;\mathrm{and}\;{\mathrm{C}_6}{\mathrm{H}_5}\mathrm{C}{\mathrm{H}_2}\mathrm{OH}

) is correct because it represents the products of a crossed Cannizzaro reaction between formaldehyde and benzaldehyde.