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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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Application +4 | -1
If a1,    a2,    a3,…,  a24{a_1},\;\;{a_2},\;\;{a_3}, \ldots ,\;{a_{24}} are in arithmetic progression and a1+a5+a10+a15+a20+a24=225,{a_1} + {a_5} + {a_{10}} + {a_{15}} + {a_{20}} + {a_{24}} = 225, then
a1+a2+a3+...+a23+a24{a_1} + {a_2} + {a_3} + ... + {a_{23}} + {a_{24}} is equal to
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Correct option: D
900
Option D (900) is correct because, in an AP, the sum of terms equidistant from the beginning and end is constant, allowing us to find the sum of all 24 terms.

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