JEE MATHEMATICS MCQ: LIMITS

1 Easy

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Analyzing +4 | -1

\lim _{x \rightarrow 1^{-}} \frac{\sqrt{\pi}-\sqrt{2 \sin ^{-1} x}}{\sqrt{1-x}}

is equal to:

View answer and explanation

Correct option: B

\sqrt{\frac{2}{\pi}}

Option B (

\sqrt{\frac{2}{\pi}}

) is correct because after applying L'Hopital's rule and simplifying, the limit evaluates to

\sqrt{\frac{2}{\pi}}

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\lim \limits_{{x \rightarrow \infty}} x\left(e^{1 / x}-1\right)

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