Question

The potential energy of a particle varies with distance x from a fixed origin as $U = \left( {\frac{{A\sqrt X }}{{x + B}}} \right);$; where A and B are constants. The dimensions of AB are

Accepted Answer

$\left[ {{\rm{M}}{{\rm{L}}^{7/2}}{{\rm{T}}^{ - 2}}} \right]$

Answer

$\left[ {{\rm{M}}{{\rm{L}}^{5/2}}{{\rm{T}}^{ - 2}}} \right]$

Answer

$\left[ {{\rm{M}}{{\rm{L}}^2}{{\rm{T}}^{ - 2}}} \right]$

Answer

$\left[ {{{\rm{M}}^{3/2}}{{\rm{L}}^{3/2}}{{\rm{T}}^{ - 2}}} \right]$

NEET UG PHYSICS MCQ: UNITS & MEASUREMENTS

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