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NEET UG PHYSICS MCQ: UNITS & MEASUREMENTS

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Application +4 | -1
What is the unit of k in the relation U=kyy2+a2U = \frac{{ky}}{{{y^2} + {a^2}}} where U represents the potential energy, y represents the displacement and a represents the maximum displacement ie, amplitude?
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Correct option: C
J m
Option C (J m) is correct because from the relation U=kyy2+a2U = \frac{{ky}}{{{y^2} + {a^2}}}, k must have the dimensions of energy times length, which corresponds to J m.

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