JEE PHYSICS MCQ: UNITS & MEASUREMENTS

1 Medium

1 of 1

Analyzing +4 | -1

Velocity of object is given as a function of time and position.

v=\alpha t+\beta x+\gamma

then dimension of

\alpha, \beta

and

\gamma

are

View answer and explanation

Correct option: B

L T^{-2}, T^{-1}, L T^{-1}

Option B (

L T^{-2}, T^{-1}, L T^{-1}

) is correct because it correctly derives the dimensions of alpha, beta, and gamma by equating the dimensions of each term in the equation.

More Questions from UNITS & MEASUREMENTS

Practice All Chapter MCQs →

\sqrt{\frac{\text { Modulus of elasticity }}{\text { Density }}}

\mathrm{ms}^{-1} \text {. }

\frac{1}{\left(\sqrt{\varepsilon_0 \mu_0}\right) t} \text {. }

\left[ {{\mathrm{M}^{ - 1}}{\mathrm{L}^{ - 3}}{\mathrm{A}^2}{T^3}} \right]

{\varepsilon _0}L\frac{{\Delta V}}{{\Delta t}},\;

{\varepsilon _0}

{\Delta V}

{\Delta t}