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JEE PHYSICS MCQ: WAVE OPTICS

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The first diffraction minimum due to single slit diffraction is

\theta

, for a light of wavelength

5000 \mathop {\text{A}}\limits^{\text{o}}

. If the width of slit is

1 \times 10^{-4} \mathrm{~cm}

. Then, the value of

\theta

is

View answer and explanation

Correct option: A

30^{\circ}

Option A (

30^{\circ}

) is correct because it is the angle calculated using the single-slit diffraction formula

d \sin \theta = \lambda

for the first minimum.

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