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JEE MATHEMATICS MCQ: COMBINATIONS

1 Easy
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Application +4 | -1
If a,b,c,d,ea,b,c,d,e are prime integers, then the number of divisors of ab2c2dea{b^2}{c^2}de excluding 1 as a factor is
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Correct option: D
71
Option D (71) is correct because the number of divisors is calculated by adding 1 to each exponent in the prime factorization, multiplying the results, and then subtracting 1 to exclude 1 as a factor.

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