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JEE MATHEMATICS MCQ: MATHEMATICAL INDUCTION

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Analyzing +4 | -1
(1)+(1+3)+(1+3+5)+…n(1)+(1+3)+(1+3+5)+\ldots n brackets is equal to
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Correct option: D
n(n+1)(2n+1)6\frac{n(n+1)(2 n+1)}{6}
Option D is correct because the sum of the terms in the nth bracket is the sum of the first n odd numbers, which is n squared, and the sum of the first n squares is given by the formula n(n+1)(2n+1)/6.

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