Skip to main content
Back to SET THEORY

JEE MATHEMATICS MCQ: SET THEORY

1 Medium
1 of 1
Application +4 | -1
If n(A∪B∪C)+n(A∪B∪C)′=50,n(A)=10,n(B)=15,n(C)=20,n(A∩B)=5,n(B∩C)=6,n(C∩A)=10,n(A∩B∩C)=5,n(A \cup B \cup C)+n(A \cup B \cup C)^{\prime}=50, n(A)=10, n(B)=15, n(C)=20, n(A \cap B)=5, n(B \cap C)=6, n(C \cap A)=10, n(A \cap B \cap C)=5, then the value of n(A∪B∪C)′n(A \cup B \cup C)^{\prime}
View answer and explanation
Correct option: B
21
Option B (21) is correct because using the principle of inclusion-exclusion to find n(A∪B∪C)n(A \cup B \cup C) and subtracting it from the total number of elements gives the correct value for n(A∪B∪C)′n(A \cup B \cup C)'.

More Questions from SET THEORY

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.