JEE MATHEMATICS MCQ: TRIGONOMETRIC EQUATIONS

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Application +4 | -1

2 \sin ^{2} x+\sin ^{2} 2 x=2,-\pi < x < \pi

, then

x=

View answer and explanation

Correct option: B

\pm \frac{\pi}{4}

Option B (

\pm \frac{{\pi}}{{4}}

) is correct because it is a solution to the trigonometric equation within the given interval.

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