Skip to main content
Back to SEQUENCE OF SERIES

JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

1 Easy
1 of 1
Application +4 | -1
If 32sin⁡2θ−1,14,34−2sin⁡2θ3^{2 \sin 2 \theta-1}, 14,3^{4-2 \sin 2 \theta} are first three terms of an A.P. for some θ\theta, then the sixth term of this A.P. is
View answer and explanation
Correct option: C
66
Option C (66) is correct because it is the sixth term of the arithmetic progression, calculated after finding the common difference.

More Questions from SEQUENCE OF SERIES

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.