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JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

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The value of
∫01(∏r=1n(x+r))(∑k=1n1x+k)dx\int_0^1\left(\prod_{r=1}^n(x+r)\right)\left(\sum\limits_{{k=1}}^n \frac{1}{x+k}\right) d x equals to
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Correct option: D
n⋅nn \cdot n !
Option D (n⋅n!n \cdot n !) is correct because the integral simplifies to the difference of the product of consecutive integers from 1 to n+1 and 1 to n, which equals n⋅n!n \cdot n !.

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