The value of $\mathop {\lim }\limits_{x \to \infty } \sqrt {{a^2}{x^2} + ax + 1} - \sqrt {{a^2}{x^2} + 1} $ is

JEE MATHEMATICS MCQ: LIMITS

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The value of

\lim\limits_{x \to \infty } \sqrt {{a^2}{x^2} + ax + 1} - \sqrt {{a^2}{x^2} + 1}

View answer and explanation

Correct option: A

\frac{1}{2}

Option A (

\frac{1}{2}

) is correct because after rationalizing and taking the limit as x approaches infinity, the expression simplifies to 1/2.

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