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JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

1 Easy
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Application +4 | -1
∫01  x21+x2  dx\int \nolimits_0^1 \,\,\frac{{{x^2}}}{{1 + {x^2}}}\,\,dx is equal to
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Correct option: D
1  −  π41\,\, - \,\,\frac{\pi }{4}
Option D (1 −  π41\, - \,\,\frac{\pi }{4}) is correct because the definite integral is evaluated by rewriting the integrand and using the arctangent integral.

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