JEE MATHEMATICS MCQ: QUADRATIC EQUATIONS

1 Easy

1 of 1

Application +4 | -1

If roots of the equation

x^2+a x+b=0

are

\alpha, \beta

, then the roots of

x^2+(2 \alpha+a) x+\alpha^2+

a \alpha+b=0

are

View answer and explanation

Correct option: C

0, \beta-\alpha

Option C (0,

\beta - \alpha

) is correct. By substituting 0 into the second equation, we find it is a root, and the other root can be found using Vieta's formulas.

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\alpha ,\beta

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\alpha ,\;\beta

{x^2} - px + q = 0

{\alpha _1},{\beta _1}

{x^2} - qx + p = 0,

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{x^2} + 4ax + 2 > 0

x

a

f\left( x \right) = a{x^2} + bx + c\;

\;f\left( { - 1} \right) < 1,f\left( 1 \right) > - 1,f\left( 3 \right) < - 4\;

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9{x^2} - 18\left| x \right| + 5 = 0

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