The basic strength of $\mathop {{\rm{CH}} \equiv \mathop {\rm{C}}\limits^\_ }\limits_I {\rm{,}}\mathop {{\rm{C}}{{\rm{H}}_2} = \mathop {\rm{C}}\limits^\_ {\rm{H}}}\limits_{II\;} ,\mathop {{\rm{C}}{{\rm{H}}_3}\mathop {\rm{C}}\limits^\_ {{\rm{H}}_2}}\limits_{III} $ Will be in order

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JEE CHEMISTRY MCQ: ORGANIC CHEMISTRY-SOME BASIC PRINCIPLES AND TECHNIQUES

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The basic strength of

\mathop {\mathrm{CH} \equiv \mathop \mathrm{C}\limits^\_ }\limits_I \mathrm{,}\mathop {\mathrm{C}{\mathrm{H}_2} = \mathop \mathrm{C}\limits^\_ \mathrm{H}}\limits_{II\;} ,\mathop {\mathrm{C}{\mathrm{H}_3}\mathop \mathrm{C}\limits^\_ {\mathrm{H}_2}}\limits_{III}

Will be in order

View answer and explanation

Correct option: A

I\mathrm{ } < II < III

Option A (

I < II < III

) is correct because the basic strength is inversely proportional to the stability of the conjugate acid, and the stability increases in the order: alkyne < alkene < alkane.

JEE CHEMISTRY MCQ: ORGANIC CHEMISTRY-SOME BASIC PRINCIPLES AND TECHNIQUES

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