JEE MATHEMATICS MCQ: PERMUTATIONS

1 Easy

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The number of proper divisors of

2^p \cdot 6^q \cdot 15^r

View answer and explanation

Correct option: B

(p+q+1)(q+r+1)(r+1)-2

Option B (

(p+q+1)(q+r+1)(r+1)-2

) is correct because it calculates the total number of divisors and then subtracts 2 to exclude 1 and the number itself, giving the number of proper divisors.

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