JEE MATHEMATICS MCQ: CIRCLES

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Analyzing +4 | -1

Let

\phi(x, y)=0

be the equation of a circle. If

\phi(0, \lambda)=0

has equal roots

\lambda=2,2

and

\phi(\lambda, 0)=0

has roots

\lambda=\frac{4}{5}, 5

, then the centre of the circle is

View answer and explanation

Correct option: B

\left(\frac{29}{10}, 2\right)

Option B ((

\frac{{29}}{{10}}

, 2)) is correct because it represents the center of the circle that satisfies the given conditions for

\phi(0, \lambda)=0

and

\phi(\lambda, 0)=0

More Questions from CIRCLES

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{\left( {{\alpha ^2}{x^2} - 2\alpha \mathrm{ }x + 1} \right)^{51}},

x

\left( {\alpha ,2{\alpha ^2}} \right)

{x^2} + {y^2} = 4,

{x^2} + {y^2} - 2x + 4y - 4 = 0

{x^2} + {y^2} = {a^2}

\left( {{x_1},{y_1}} \right)

\quad \alpha, \beta

\gamma

P, Q

x^2+y^2=1

A

(-1,0)

A P, A Q

A R

G P

\cos \alpha / 2, \cos \beta / 2

\cos \gamma / 2

x+y=6

x+2 y=4

x+y=5

x-y=1

9 \pi