JEE MATHEMATICS MCQ: TRIGONOMETRIC EQUATIONS

1 Easy

1 of 1

Analyzing +4 | -1

The number of solutions of the equation

1 + \sin \,\,x\,\,{\sin ^2}\,\,\frac{x}{2} = 0

, in

\left[ { - \pi ,\,\;\pi } \right]

View answer and explanation

Correct option: A

Zero

Option A (Zero) is correct because the equation

1 + \sin x \sin^2 \frac{x}{2} = 0

has no solutions in the interval

[-\pi, \pi]

since the expression is always positive.

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