Question

Choose the correct statement

Accepted Answer

High negative $\mathrm{E}^{\circ}$ value for $\mathrm{Zn}$ owing to completely filled $3 \mathrm{d}$ subshell in $\mathrm{Zn}^{2+}$

Answer

$\mathrm{Cr}^{2+}$ is weaker reducing agent than $\mathrm{Fe}^{2+}$

Answer

Generally metal in metal fluorides exhibits higher oxidation state than in metal oxides

Answer

${	ext{E}}_{\left( {{	ext{M}}{{	ext{n}}^{2 + }}{	ext{/Mn}}} ight)}^{\circ}$ is more negative than ${	ext{E}}_{\left( {{	ext{C}}{{	ext{r}}^{2 + }}{	ext{/Cr}}} ight)}^{\circ}$ due to relatively high sublimation energy of $\mathrm{Mn}$

JEE CHEMISTRY MCQ: d & f- BLOCK ELEMENTS

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