JEE MATHEMATICS MCQ: LIMITS

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\lim\limits_{x \to 1} \left( {\frac{{\int\limits_0^{{{(x - 1)}^2}} {t\cos ({t^2})dt} }}{{(x - 1)\sin (x - 1)}}} \right)

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Correct option: D

Option D is correct because by applying L'Hopital's rule twice, the limit evaluates to 0.

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