NEET UG PHYSICS MCQ: MOTION IN PLANE

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A body is under the action of two mutually perpendicular forces of 3 N and 4 N. The resultant force acting on the body is

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Correct option: C

5 N

Option C (5 N) is correct because the resultant of two perpendicular forces is found using the Pythagorean theorem.

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\mathrm{\vec a}\,and\,\mathrm{\vec b}

\mathrm{\vec a}\,and\,\mathrm{\vec b}

\overrightarrow P \,\,.\,\,\overrightarrow Q = 0\,and\,\overrightarrow P \,\, \times \,\,\overrightarrow Q = 0

\overrightarrow Q \,and\,\overrightarrow R

\vec{A}=3 \hat{i}+4 \hat{j}

\vec{B}=6 \hat{i}+8 \hat{j}

A

B

\overrightarrow{\mathrm{A}}

\overrightarrow{\mathrm{B}}

{\cot ^{ - 1}}\left( 2 \right)