NEET UG CHEMISTRY MCQ: CO-ORDINATION COMPOUNDS

1 Easy

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Application +4 | -1

The pair of compounds having metals in their highest oxidation state is

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Correct option: B

{\left[ {\mathrm{Mn}{\mathrm{O}_4}} \right]^ - },\mathrm{Cr}{\mathrm{O}_2}\mathrm{C}{\mathrm{l}_2}

Option B (

{\left[ {\mathrm{Mn}{\mathrm{O}_4}} \right]^ - },\mathrm{Cr}{\mathrm{O}_2}\mathrm{C}{\mathrm{l}_2}

) is correct because Mn in

{\left[ {\mathrm{Mn}{\mathrm{O}_4}} \right]^ - }

and Cr in

\mathrm{Cr}{\mathrm{O}_2}\mathrm{C}{\mathrm{l}_2}

are in their highest oxidation states, +7 and +6 respectively.

More Questions from CO-ORDINATION COMPOUNDS

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\left[ {\mathrm{PtC}{\mathrm{l}_2}{{\left( {\mathrm{N}{\mathrm{H}_3}} \right)}_4}} \right]\mathrm{B}{\mathrm{r}_2}\mathrm{\;and\;}\left[ {\mathrm{PtB}{\mathrm{r}_2}{{\left( {\mathrm{N}{\mathrm{H}_3}} \right)}_4}} \right]\mathrm{C}{\mathrm{l}_2}\mathrm{\;}

\left[\mathrm{Cr}(\mathrm{Ox})_{2} \mathrm{ClBr}\right]^{3-}

\text{ox =}

x

{\left[ {\mathrm{Ni}{{\left( {\mathrm{CN}} \right)}_4}} \right]^x}

\mathrm{M}{\mathrm{n}^{2 + }}

\mathrm{CuS}{\mathrm{O}_4}

{\mathrm{K}_2}\left[ {\mathrm{Ni}{{\left( {\mathrm{CN}} \right)}_4}} \right]