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JEE PHYSICS MCQ: ELECTROMAGNETIC WAVES

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In a plane electromagnetic wave, the electric field varies with time having an amplitude 1 Vm−11 \mathrm{~Vm}^{-1}. The frequency of wave is 0.5×1015 Hz0.5 \times 10^{15} \mathrm{~Hz}. The wave is propagating along zz-axis. What is the average amplitude of magnetic field?
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Correct option: A
3.33×10−9 T3.33 \times 10^{-9} \mathrm{~T}
Option A (3.33×10−9 T3.33 \times 10^{-9} \mathrm{~T}) is correct because it is calculated using the relationship between the electric field amplitude and the magnetic field amplitude in an electromagnetic wave, B0=E0/cB_0 = E_0/c.

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