Back to PERMUTATIONS
JEE MATHEMATICS MCQ: PERMUTATIONS
1
Medium
1 of 1
Application
+4 | -1
Number of ways in which four prize can be given away to 8 students when a students can get any number of prize is
View answer and explanation
Correct option: B
Option D (None of these) is correct. There appears to be an error in the provided solution. The correct approach involves derangements, and the number of functions f: A -> B such that f(i) != a_i is given by the number of derangements of 5 elements, which is 44. Therefore, none of the given options are correct.
More Questions from PERMUTATIONS
Practice All Chapter MCQs →
How many different nine digit numbers can be formed from the number 223355888 by rearranging its digits so that the odd digits occupy even positions?
The number of ways in which letters can be posted in letterboxes in a town is
The number of four-digit numbers that can be made with the digits and 5 in which atleast two digits are identical, is
The number of ways in which a pack of 52 cards can be divided equally into four groups, is
Five digited numbers with distinct digits are formed by using the digits, 5, 4, 3, 2, 1, 0. The number of those numbers which are multiples of 3, is
A man invites a party to friends to dinner and places m at one round table and at another. The number of ways of arranging the guests is
