JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

1 Easy

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Analyzing +4 | -1

Let

a_n

be the

n^{\text {th }}

term of the G.P. of positive numbers. Let

\sum\limits_{n=1}^{100} a_{2 n}=\alpha

and

\sum\limits_{n=1}^{100} a_{2 n-1}=\beta

, such that

\alpha \neq \beta

, then the common ratio is

View answer and explanation

Correct option: A

\alpha / \beta

Option A (

\alpha / \beta

) is correct because the common ratio of the G.P. can be found by dividing the sum of even-indexed terms by the sum of odd-indexed terms.

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