JEE MATHEMATICS MCQ: CIRCLES

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Analyzing +4 | -1

If each of the lines

5 x+8 y=13

and

4 x-y=3

contains a diameter of the circle

x^{2}+y^{2}-2\left(a^{2}-7 a+11\right) x-2\left(a^{2}-6 a+6\right) y+b^{3}+1=0

, then

View answer and explanation

Correct option: D

a=5

and

b \in(-\infty, 1)

Option D (

a=5

and

b \in(-\infty, 1)

) is correct because the center of the circle must be the intersection of the diameters, and the radius must be real.

More Questions from CIRCLES

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{\left( {{\alpha ^2}{x^2} - 2\alpha \mathrm{ }x + 1} \right)^{51}},

x

\left( {\alpha ,2{\alpha ^2}} \right)

{x^2} + {y^2} = 4,

{x^2} + {y^2} - 2x + 4y - 4 = 0

{x^2} + {y^2} = {a^2}

\left( {{x_1},{y_1}} \right)

\quad \alpha, \beta

\gamma

P, Q

x^2+y^2=1

A

(-1,0)

A P, A Q

A R

G P

\cos \alpha / 2, \cos \beta / 2

\cos \gamma / 2

x+y=6

x+2 y=4

x+y=5

x-y=1

9 \pi