NEET UG PHYSICS MCQ: MOTION IN PLANE

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Application +4 | -1

The resultant of two forces, each P, acting at an angle

\theta

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Correct option: B

2P Cos

\frac{\mathrm{\theta }}{2}

Option B (2P Cos

\frac{\mathrm{\theta }}{2}

) is correct because the resultant of two forces of equal magnitude P acting at an angle

\theta

is given by

R = \sqrt{P^2 + P^2 + 2P^2 \cos \theta} = \sqrt{2P^2(1 + \cos \theta)} = \sqrt{2P^2(2 \cos^2 \frac{\theta}{2})} = 2P \cos \frac{\theta}{2}

More Questions from MOTION IN PLANE

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\mathrm{\vec a}\,and\,\mathrm{\vec b}

\mathrm{\vec a}\,and\,\mathrm{\vec b}

\overrightarrow P \,\,.\,\,\overrightarrow Q = 0\,and\,\overrightarrow P \,\, \times \,\,\overrightarrow Q = 0

\overrightarrow Q \,and\,\overrightarrow R

\vec{A}=3 \hat{i}+4 \hat{j}

\vec{B}=6 \hat{i}+8 \hat{j}

A

B

\overrightarrow{\mathrm{A}}

\overrightarrow{\mathrm{B}}

{\cot ^{ - 1}}\left( 2 \right)