Skip to main content
Back to DEFINITE INTEGRATION

JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

1 Medium
1 of 1
Application +4 | -1
Evaluate ∫01/2xsin⁡−1x1−x2dx.\int\limits_{0}^{1 / 2} \frac{x \sin ^{-1} x}{\sqrt{1-x^2}} d x.
View answer and explanation
Correct option: A
6−π312\frac{6-\pi \sqrt{3}}{12}
Option A (6−π312\frac{{6-\pi \sqrt{{3}}}}{{12}}) is correct because the integral is solved using trigonometric substitution and integration by parts.

More Questions from DEFINITE INTEGRATION

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.