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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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21/4⋅41/1681/48.....{2^{1/4}} \cdot {4^{1/16}}{8^{1/48}}..... to ∞\infty is equal to
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Correct option: A
2\sqrt{2}
Option A (2\sqrt{2}) is the correct answer because the expression simplifies to 21/22^{1/2}, which is the square root of 2.

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