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JEE MATHEMATICS MCQ: PERMUTATIONS

1 Easy
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Application +4 | -1
If nPr=2520{ }^{{n}} P_{{r}}=2520 and nCr=21{ }^{{n}} C_{{r}}=21 then nn is equal to:
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Correct option: B
7
Option B (7) is correct because by using the given values of nPr{}^{{n}} P_{{r}} and nCr{}^{{n}} C_{{r}}, we can find r=5 and then solve for n, which results in n=7.

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