JEE PHYSICS MCQ: KINETIC THEORY OF GASES

1 Medium

1 of 1

Understanding +4 | -1

The mean free path for a gas, with molecular diameter

d

and number density

n

can be expressed as

\left(T \text{ is temperature, }P \text{ is pressure of the gas and }k_B \text{ is Boltzmann constant}\right)

View answer and explanation

Correct option: D

Both (2) and (3)

Option D is correct because the mean free path can be expressed in terms of number density and molecular diameter, or in terms of pressure, temperature, and Boltzmann constant.

More Questions from KINETIC THEORY OF GASES

Practice All Chapter MCQs →

Assertion: The pressure exerted by an enclosed ideal gas does not depend on the shape of the container.
Reason: The pressure of an ideal gas depends on the number moles, temperature and volume of the enclosed If

c_s

is the velocity of sound in air and

c

is the rms velocity, then Four particles have velocities

1,0,2,3 \mathrm{~m} / \mathrm{s}

. The root mean square of the particles is (in

\mathrm{m} / \mathrm{s}

) The translational degrees of freedom

(f_t)

and rotational degrees of freedom

(f_r)

{CH}_4

molecule are: On any planet, the presence of atmosphere implies (

{C_{rms}} =

= root mean square velocity of molecules and

{V_e} =

escape velocity) At a given temperature, the pressure of an ideal gas of density

\rho

is proportional to