JEE MATHEMATICS MCQ: STRAIGHT LINES

1 Easy

1 of 1

Application +4 | -1

The equation of a straight line which cut off an intercept of 5 units on negative direction of

Y

-axis and make an angle of

120^{\circ}

with positive direction of

X

-axis, is

View answer and explanation

Correct option: B

y+\sqrt{3} x+5=0

Option B (

y+\sqrt{3} x+5=0

) is correct because the equation of a line is

y = mx + c

, where

m

is the slope and

c

is the y-intercept. Given the angle and y-intercept, we can find the equation.

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y = 2\;x + 4

6x = 3y + 5

{x^2} + {y^2} + 2xy - 8ax - 8ay - 9{a^2} = 0

(3,8)

x+3 y=7

\left( {{x^2} + 7xy + 2{y^2}} \right)\left( {y - 1} \right) = 0