Let $f(x)=\sqrt{3}-x+\sqrt{x+2}$. The range of $f(x)$ is

JEE MATHEMATICS MCQ: FUNCTIONS

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Analyzing +4 | -1

Let

f(x)=\sqrt{3}-x+\sqrt{x+2}

. The range of

f(x)

View answer and explanation

Correct option: B

[\sqrt{5}, \sqrt{10}]

Option B (

[\sqrt{5}, \sqrt{10}]

) is correct because it accurately determines the range of the function by finding its critical points and endpoints.

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