Skip to main content
Back to HYPERBOLA

JEE MATHEMATICS MCQ: HYPERBOLA

1 Easy
1 of 1
Application +4 | -1
The equation of the conic with focus at (1,−1),\left( {1, - 1} \right), directrix along x−y+1=0x - y + 1 = 0 and with eccentricity 2\sqrt 2 is
View answer and explanation
Correct option: C
2xy−4x+4y+1=02xy - 4x + 4y + 1 = 0
Option C (2xy−4x+4y+1=02xy - 4x + 4y + 1 = 0) is the correct conic equation because it satisfies the definition of a conic section with the given focus, directrix, and eccentricity.

More Questions from HYPERBOLA

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.