JEE PHYSICS MCQ: RAY OPTICS

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An object is placed 21 cm in front of a concave mirror of radius of curvature 10 cm. A glass slab of thickness 3 cm and refractive index 3/2 is then placed close to the mirror the space between the object and the mirror. Distance of the near surface of the slab from the mirror is 1 cm. Find the position of the final image formed:-

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Correct option: A

7.67 cm

Option A (7.67 cm) is correct because it accounts for the shift due to the glass slab and the reflection from the concave mirror.

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