JEE MATHEMATICS MCQ: ELLIPSE

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Analyzing +4 | -1

The locus of the poles of tangents to the director circle of the ellipse

\frac{{{x^2}}}{{{a^2}}} + \frac{{{y^2}}}{{{b^2}}} = 1

with respect to the ellipse

\frac{{{x^2}}}{{{a^2}}} + \frac{{{y^2}}}{{{b^2}}} = 1,

View answer and explanation

Correct option: B

\frac{{{x^2}}}{{{a^4}}} + \frac{{{y^2}}}{{{a^4}}} = \frac{1}{{{a^2} + {b^2}}}

Option B (

\frac{{{x^2}}}{{{a^4}}} + \frac{{{y^2}}}{{{b^4}}} = \frac{1}{{{a^2} + {b^2}}}

) is correct because it represents the locus of the poles of tangents to the director circle with respect to the given ellipse.

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