JEE PHYSICS MCQ: ELECTRIC FIELDS AND CHARGES

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A positive charge particle of

100 \,\mathrm{mg}

is thrown in opposite direction to a uniform electric field of strength

1 \times 10^5 \,\mathrm{NC}^{-1}

. If the charge on the particle is

40 \mu \mathrm{C}

and the initial velocity is

200 \mathrm{~ms}^{-1}

, how much distance it will travel before coming to the rest momentarily?

View answer and explanation

Correct option: D

0.5 \mathrm{~m}

Option D (0.5 m) is correct because it is the distance the charged particle travels before coming to rest, calculated using kinematics and the electric force.

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