Two wires that are made up of two different materials whose specific resistance are in the ratio ${\rm{2 : 3}}$, length ${\rm{3 : 4}}$ and area ${\rm{4 : 5}}$. The ratio of their resistances is

$\begin{array}{*{20}{l}} {{\rm{5 : 8}}} \end{array}$

$\begin{array}{*{20}{l}} {{\rm{6 : 5}}} \end{array}$

$\begin{array}{*{20}{l}} {{\rm{6 : 8}}} \end{array}$

$\begin{array}{*{20}{l}} {{\rm{1 : 2}}} \end{array}$

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JEE PHYSICS MCQ: CURRENT ELECTRICITY

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Application +4 | -1

Two wires that are made up of two different materials whose specific resistance are in the ratio

\mathrm{2 : 3}

, length

\mathrm{3 : 4}

and area

\mathrm{4 : 5}

. The ratio of their resistances is

View answer and explanation

Correct option: C

\begin{array}{llllllllllllllllllll} {\mathrm{5 : 8}} \end{array}

Option C (5 : 8) is correct because the ratio of resistances is calculated using the formula R = ρl/A, considering the given ratios of specific resistance, length, and area.

JEE PHYSICS MCQ: CURRENT ELECTRICITY

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