JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

1 Easy

1 of 1

Application +4 | -1

\mathrm{g}\left( x \right) = \frac{{f\left( x \right) - f\left( { - x} \right)}}{2}

defined over

\left[ { - \,3,\,\,3} \right]

and

f\left( x \right) = 2{x^2} - 4x + 1

, then

\int \nolimits_{ - 3}^3 \,\,\,\mathrm{g}\,\,\left( x \right)\,\,dx

is equal to

View answer and explanation

Correct option: A

\begin{array}{llllllllllllllllllll} \mathrm{0} \end{array}

Option A is correct because the integral of the odd function g(x) over the symmetric interval [-3, 3] is 0.

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