JEE MATHEMATICS MCQ: ELLIPSE

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Application +4 | -1

The locus of the pole of any tangent to the auxiliary circle w.r.t. the ellipse

\frac{x^2}{a^2}+\frac{y^2}{b^2}=1

View answer and explanation

Correct option: D

b^4 x^2+a^4 y^2=a^2 b^4

Option A (

b^4 x^2+a^4 y^2=a^2 b^4

) is correct because it is derived by finding the pole of a tangent to the auxiliary circle with respect to the ellipse.

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