If $z=x+i y$ satisfies $|z|-2=0$ and $|z-i|-|z+5 i|$ $=0$, then

JEE MATHEMATICS MCQ: COMPLEX NUMBERS

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Analyzing +4 | -1

z=x+i y

satisfies

|z|-2=0

and

|z-i|-|z+5 i|

=0

, then

View answer and explanation

Correct option: C

x+2 y+4=0

Option C (

x+2 y+4=0

) is correct because the equation represents the perpendicular bisector of the line segment joining (0,1) and (0,-5), and the intersection with |z|=2 gives the solution.

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The number of non-zero integer solutions of the equation

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Let

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where

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is If

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